Firefly villain costume leaked on Batgirl

The villain Firefly, played by Brendan Fraser, has been leaked on the set of Batgirl. We show you the design they have given it!

The shooting of batgirl for hbo max is still active in Glasgow (Scotland). We have previously seen the return of the Batman by Michael Keaton, which has given us goosebumps. However, now we have a first look at the outfit he will wear. brendan fraser to bring the villain to life DC Comics known as Firefly. We share here a filtered image and a couple of videos that have appeared on social media:

We do not know for sure if we are actually seeing the actor from The Doom Patrol under Firefly’s mask. Most likely, it is a stuntman who is working on the set of batgirl. Be that as it may, the outfit to be very inspired by the version of the villain that the video games of batman arkham. We show you an image of this iteration for you to check:


Firefly in the Batman: Arkham video games
Batman chases Firefly in the “Arkham” saga of video games

What do you think? Do you think they have been inspired by this version? We have it quite clear, really.

The version of this villain will be the one after “Crisis on Infinite Earths”

Although there was some uncertainty surrounding Brendan Fraser’s role in batgirl when his casting was announced, since then we have known many details. It has been confirmed that he will play the villain garfield lynns and that is saying enough. We still don’t know how they will adapt the character, how they will represent her or what connection she will have with Barbara Gordon as Leslie Grace. Based on everything that has come to light, we can guess a few things. For example, it seems that the sociopathic arsonist Firefly that we are going to have here will be the villain that they presented after the events of Crisis on Infinite Earths.

The film will not see the light, presumably, until next year. It remains to be seen if it will be released only on HBO Max or if, on the contrary, it will be released simultaneously in theaters.